3v^2=11v+60

Solution for 3v^2=11v+60 equation:

3v^2=11v+60

We move all terms to the left:

3v^2-(11v+60)=0

We get rid of parentheses

3v^2-11v-60=0

a = 3; b = -11; c = -60;
Δ = b2-4ac
Δ = -112-4·3·(-60)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-29}{2*3}=\frac{-18}{6}
=-3
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+29}{2*3}=\frac{40}{6}
=6+2/3
$